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author | Joseph Hunkeler <jhunkeler@gmail.com> | 2015-03-04 21:21:30 -0500 |
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committer | Joseph Hunkeler <jhunkeler@gmail.com> | 2015-03-04 21:21:30 -0500 |
commit | d54fe7c1f704a63824c5bfa0ece65245572e9b27 (patch) | |
tree | afc52015ffc2c74e0266653eecef1c8ef8ba5d91 /src/slalib/invf.f | |
download | calfuse-d54fe7c1f704a63824c5bfa0ece65245572e9b27.tar.gz |
Initial commit
Diffstat (limited to 'src/slalib/invf.f')
-rw-r--r-- | src/slalib/invf.f | 90 |
1 files changed, 90 insertions, 0 deletions
diff --git a/src/slalib/invf.f b/src/slalib/invf.f new file mode 100644 index 0000000..f323228 --- /dev/null +++ b/src/slalib/invf.f @@ -0,0 +1,90 @@ + SUBROUTINE sla_INVF (FWDS,BKWDS,J) +*+ +* - - - - - +* I N V F +* - - - - - +* +* Invert a linear model of the type produced by the +* sla_FITXY routine. +* +* Given: +* FWDS d(6) model coefficients +* +* Returned: +* BKWDS d(6) inverse model +* J i status: 0 = OK, -1 = no inverse +* +* The models relate two sets of [X,Y] coordinates as follows. +* Naming the elements of FWDS: +* +* FWDS(1) = A +* FWDS(2) = B +* FWDS(3) = C +* FWDS(4) = D +* FWDS(5) = E +* FWDS(6) = F +* +* where two sets of coordinates [X1,Y1] and [X2,Y1] are related +* thus: +* +* X2 = A + B*X1 + C*Y1 +* Y2 = D + E*X1 + F*Y1 +* +* the present routine generates a new set of coefficients: +* +* BKWDS(1) = P +* BKWDS(2) = Q +* BKWDS(3) = R +* BKWDS(4) = S +* BKWDS(5) = T +* BKWDS(6) = U +* +* such that: +* +* X1 = P + Q*X2 + R*Y2 +* Y1 = S + T*X2 + U*Y2 +* +* Two successive calls to sla_INVF will thus deliver a set +* of coefficients equal to the starting values. +* +* To comply with the ANSI Fortran standard, FWDS and BKWDS must +* not be the same array, even though the routine is coded to +* work on the VAX and most other computers even if this rule +* is violated. +* +* See also sla_FITXY, sla_PXY, sla_XY2XY, sla_DCMPF +* +* P.T.Wallace Starlink 11 April 1990 +* +* Copyright (C) 1995 Rutherford Appleton Laboratory +*- + + IMPLICIT NONE + + DOUBLE PRECISION FWDS(6),BKWDS(6) + INTEGER J + + DOUBLE PRECISION A,B,C,D,E,F,DET + + + + A=FWDS(1) + B=FWDS(2) + C=FWDS(3) + D=FWDS(4) + E=FWDS(5) + F=FWDS(6) + DET=B*F-C*E + IF (DET.NE.0D0) THEN + BKWDS(1)=(C*D-A*F)/DET + BKWDS(2)=F/DET + BKWDS(3)=-C/DET + BKWDS(4)=(A*E-B*D)/DET + BKWDS(5)=-E/DET + BKWDS(6)=B/DET + J=0 + ELSE + J=-1 + END IF + + END |