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C----------------------------------------------------------------------
subroutine ftcpdt(iunit,ounit,status)
C copies the data from the IUNIT CHDU to the data of the OUNIT CHDU.
C This will overwrite any data already in the OUNIT CHDU.
C iunit i fortran unit number of the input file to be copied
C ounit i fortran unit number of the output file to be copied to
C status i output error status
C
C written by Wm Pence, HEASARC/GSFC, Aug 1993
integer iunit,ounit,status
C COMMON BLOCK DEFINITIONS:--------------------------------------------
integer nb,ne
parameter (nb = 20)
parameter (ne = 200)
integer bufnum,chdu,hdutyp,maxhdu,hdstrt,hdend,nxthdr,dtstrt
integer nxtfld
logical wrmode
common/ft0001/bufnum(199),chdu(nb),hdutyp(nb),maxhdu(nb),
& wrmode(nb),hdstrt(nb,ne),hdend(nb),nxthdr(nb),dtstrt(nb),nxtfld
character*1 cbuff(2880), xdummy(2880)
common/ftheap/cbuff,xdummy
C END OF COMMON BLOCK DEFINITIONS-----------------------------------
integer ibuff,obuff,nblock,i
if (status .gt. 0)return
if (iunit .eq. ounit)then
status=101
return
end if
ibuff=bufnum(iunit)
obuff=bufnum(ounit)
C determine HDU structure as defined by keywords in output file
call ftrdef(ounit,status)
C Calculate the number of bytes to be copied. By definition there
C will be an integral number of 2880-byte logical blocks to be copied
nblock=(hdstrt(ibuff,chdu(ibuff)+1)-dtstrt(ibuff))/2880
if (nblock .gt. 0)then
C move to the beginning of the data in the input and output files
call ftmbyt(iunit,dtstrt(ibuff),.false.,status)
call ftmbyt(ounit,dtstrt(obuff),.true.,status)
C now copy the data one block at a time
do 30 i=1,nblock
call ftgcbf(iunit,0,2880,cbuff,status)
call ftpcbf(ounit,0,2880,cbuff,status)
30 continue
end if
end
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