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C--------------------------------------------------------------------------
subroutine ftmkys(ounit,keywrd,strval,comm,status)
C modify a character string value header record
C
C ounit i fortran output unit number
C keywrd c keyword name ( 8 characters, cols. 1- 8)
C strval c keyword value
C comm c keyword comment (47 characters, cols. 34-80)
C OUTPUT PARAMETERS:
C status i output error status (0 = ok)
C
C written by Wm Pence, HEASARC/GSFC, June 1991
C modifed 7/93 to support string keywords continued over multiple cards
C modified 9/94 to support the OGIP long string convention
character*(*) keywrd,strval,comm
integer ounit,status
integer clen,i,nvalue,ncomm
character keynam*8,value*70,cmnt*48,bslash
C-------COMMON BLOCK DEFINITIONS:--------------------------------------------
integer nb,ne
parameter (nb = 20)
parameter (ne = 200)
integer bufnum,chdu,hdutyp,maxhdu,hdstrt,hdend,nxthdr,dtstrt
integer nxtfld
logical wrmode
common/ft0001/bufnum(199),chdu(nb),hdutyp(nb),maxhdu(nb),
& wrmode(nb),hdstrt(nb,ne),hdend(nb),nxthdr(nb),dtstrt(nb),nxtfld
C-------END OF COMMON BLOCK DEFINITIONS-----------------------------------
if (status .gt. 0)return
C check if the new value is too long to fit in a single 'card image'
clen=len(strval)
if (clen .le. 68)go to 20
do 10 i=clen,69,-1
if (strval(i:i) .ne. ' ')go to 100
10 continue
C now check that the old keyword is not continued over multiple cards
C read the (first line) of the existing keyword
20 call ftgkey(ounit,keywrd,value,cmnt,status)
if (status .gt. 0)go to 900
C is last character of the value a backslash or & ?
C have to use 2 \\'s because the SUN compiler treats 1 \ as an escape
bslash='\\'
do 30 i=70,1,-1
if (value(i:i) .ne. ' '.and. value(i:i).ne.'''')then
if (value(i:i) .eq. bslash .or.
& value(i:i) .eq. '&')then
C backspace the current header pointer by one record
nxthdr(bufnum(ounit))=nxthdr(bufnum(ounit))-80
go to 100
else
go to 40
end if
end if
30 continue
C OK, we can simply overwrite the old keyword with the new
40 continue
C overwrite the old comment unless user supplied the magic value
if (comm .ne. '&')then
cmnt=comm
end if
C convert string to quoted character string (max length = 70 characters)
call fts2c(strval,value,clen,status)
if (status .gt. 0)go to 900
C find amount of space left for comment string
C (assume 10 char. for 'keyword = ', and 3 between value and comment)
C which leaves 67 spaces for the value string + comment string
nvalue=max(20,clen)
ncomm=67-nvalue
C write the keyword record
keynam=keywrd
if (ncomm .gt. 0)then
C there is space for a comment
call ftmodr(ounit,
& keynam//'= '//value(1:nvalue)//' / '//cmnt(1:ncomm),status)
else
C no room for a comment
call ftmodr(ounit,
& keynam//'= '//value(1:nvalue)//' ',status)
end if
go to 900
100 continue
C Either the old or new keyword is continued over multiple
C header card images, so have to use a less efficient way to modify
C the keyword by completely deleting the old and inserting the new.
C read the old comment, if we need to preserve it
if (comm .eq. '&')then
call ftgkys(ounit,keywrd,value,cmnt,status)
if (status .gt. 0)go to 900
C reset the current header pointer by 2 records to make
C it faster (usually) to find and delete the keyword
nxthdr(bufnum(ounit))=nxthdr(bufnum(ounit))-160
else
cmnt=comm
end if
C delete the old keyword
call ftdkey(ounit,keywrd,status)
if (status .gt. 0)go to 900
C insert the new keyword
call ftikys(ounit,keywrd,strval,cmnt,status)
900 continue
end
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