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C--------------------------------------------------------------------------
subroutine ftprec(ounit,record,status)
C write a 80 character record to the FITS header
C
C ounit i fortran output unit number
C record c input 80 character header record
C OUTPUT PARAMETERS:
C status i output error status (0 = ok)
C
C written by Wm Pence, HEASARC/GSFC, June 1991
character*(*) record
character*80 rec
integer ounit,status,ibuff
C-------COMMON BLOCK DEFINITIONS:--------------------------------------------
integer nb,ne
parameter (nb = 20)
parameter (ne = 200)
integer bufnum,chdu,hdutyp,maxhdu,hdstrt,hdend,nxthdr,dtstrt
integer nxtfld
logical wrmode
common/ft0001/bufnum(199),chdu(nb),hdutyp(nb),maxhdu(nb),
& wrmode(nb),hdstrt(nb,ne),hdend(nb),nxthdr(nb),dtstrt(nb),nxtfld
C-------END OF COMMON BLOCK DEFINITIONS:------- -----------------------------
if (status .gt. 0)return
C get the number of the data buffer used for this unit
ibuff=bufnum(ounit)
if (dtstrt(ibuff) .gt. 0
& .and.(dtstrt(ibuff)-hdend(ibuff)) .le. 80)then
C not enough room in the header for another keyword
C try getting more header space
call ftiblk(ounit,1,0,status)
if (status .gt. 0)then
go to 900
end if
end if
rec=record
C make sure keyword name is in upper case
call ftupch(rec(1:8))
C test that keyword name contains only legal characters
call fttkey(rec(1:8),status)
C test that the rest of the record contains only legal values
call fttrec(rec(9:80),status)
C position the I/O pointer to the end of the header
call ftmbyt(ounit,hdend(ibuff),.true.,status)
C append the 80 characters to the output buffer:
call ftpcbf(ounit,1,80,rec,status)
if (status .gt. 0)go to 900
C increment the pointer to the last header record
hdend(ibuff)=hdend(ibuff)+80
nxthdr(ibuff)=hdend(ibuff)
900 continue
end
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